Matematika tentukan nilai setiap operasi bilangan berikuta.9√2+√72-3√50=9√2+√...×...×..-(3√...×...) =9√2+(...×...)√...-3×...√... =9√2+...√...-...√ =...√...b. 5√3(√50+√98)=5√3(...√...+...√...) =5√3(...√...) =...√...tolong juga ya kak ini tugas di kumpulin besok​

sibylwittingulv – April 07, 2023

tentukan nilai setiap operasi bilangan berikut

a.9√2+√72-3√50=9√2+√...×...×..-(3√...×...)
=9√2+(...×...)√...-3×...√...
=9√2+...√...-...√
=...√...

b. 5√3(√50+√98)=5√3(...√...+...√...)
=5√3(...√...)
=...√...

tolong juga ya kak ini tugas di kumpulin besok​

SOAL A.

[tex]9 \sqrt{2} + \sqrt{72} - 3 \sqrt{50} [/tex]

[tex]= 9 \sqrt{2} + \sqrt{36 \times 2} - 3 \sqrt{25 \times 2} [/tex]

[tex]= 9 \sqrt{2} + 6 \sqrt{2} - 3 \times 5 \sqrt{2} [/tex]

[tex]= 9 \sqrt{2} + 6 \sqrt{2} - 15 \sqrt{2} [/tex]

[tex]= (9 + 6 - 15) \sqrt{2} = (0) \sqrt{2} = 0 [/tex]

SOAL B.

[tex]5 \sqrt{3} \: (\sqrt{50} + \sqrt{98})[/tex]

[tex]= 5 \sqrt{3} \: (\sqrt{25 \times 2} + \sqrt{49 \times 2})[/tex]

[tex]= 5 \sqrt{3} \: (5 \sqrt{2} + 7 \sqrt{2}) [/tex]

[tex]= 5 \sqrt{3} \: ((5 + 7) \sqrt{2})[/tex]

[tex]= 5 \sqrt{3} \: (12 \sqrt{2})[/tex]

[tex]= (5 \times 12) \sqrt{(3 \times 2)} [/tex]

[tex]= 60 \sqrt{6} [/tex]

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